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ベクトルの公式


$\displaystyle \boldsymbol{A}\cdot\boldsymbol{B}$ $\displaystyle =$ $\displaystyle \boldsymbol{B}\cdot\boldsymbol{C}$ (729)
$\displaystyle \boldsymbol{A}\times\boldsymbol{B}$ $\displaystyle =$ $\displaystyle -\boldsymbol{B}\times\boldsymbol{C}$ (730)
$\displaystyle \boldsymbol{A}\cdot(\boldsymbol{B}\times\boldsymbol{C})$ $\displaystyle =$ $\displaystyle \boldsymbol{B}\cdot(\boldsymbol{C}\times\boldsymbol{A})
=\boldsymbol{C}\cdot(\boldsymbol{A}\times\boldsymbol{B})$ (731)
$\displaystyle \boldsymbol{A}\times(\boldsymbol{B}\times\boldsymbol{C})$ $\displaystyle =$ $\displaystyle (\boldsymbol{A}\cdot\boldsymbol{C})\boldsymbol{B}-(\boldsymbol{A}\cdot\boldsymbol{B})\boldsymbol{C}$ (732)
       
$\displaystyle \mathop\emph{\text{grad}}\nolimits (fg)$ $\displaystyle =$ $\displaystyle f\mathop\emph{\text{grad}}\nolimits g+g\mathop\emph{\text{grad}}\nolimits f$ (733)
$\displaystyle \mathop\emph{\text{div}}\nolimits (f\boldsymbol{A})$ $\displaystyle =$ $\displaystyle \boldsymbol{A}\mathop\emph{\text{grad}}\nolimits f+f\mathop\emph{\text{div}}\nolimits \boldsymbol{A}$ (734)
$\displaystyle \mathop\emph{\text{rot}}\nolimits (f\boldsymbol{A})$ $\displaystyle =$ $\displaystyle f\mathop\emph{\text{rot}}\nolimits \boldsymbol{A}+\mathop\emph{\text{grad}}\nolimits f\times\boldsymbol{A}$ (735)
$\displaystyle \mathop\emph{\text{grad}}\nolimits (\boldsymbol{A}\cdot\boldsymbol{B})$ $\displaystyle =$ $\displaystyle (\boldsymbol{B}\cdot\mathop{\emph ▽}\nolimits )\boldsymbol{A}
+(\boldsymbol{A}\cdot\mathop{\emph ▽}\nolimits )\boldsymbol{B}$  
    $\displaystyle +\boldsymbol{A}\times\mathop\emph{\text{rot}}\nolimits \boldsymbol{B}+\boldsymbol{B}\times\mathop\emph{\text{rot}}\nolimits \boldsymbol{A}$ (736)
$\displaystyle \mathop\emph{\text{div}}\nolimits (\boldsymbol{A}\times\boldsymbol{B})$ $\displaystyle =$ $\displaystyle \boldsymbol{B}\mathop\emph{\text{rot}}\nolimits \boldsymbol{A}-\boldsymbol{A}\mathop\emph{\text{rot}}\nolimits \boldsymbol{B}$ (737)
$\displaystyle \mathop\emph{\text{rot}}\nolimits (\boldsymbol{A}\times\boldsymbol{B})$ $\displaystyle =$ $\displaystyle \boldsymbol{A}\mathop\emph{\text{div}}\nolimits \boldsymbol{B}-\boldsymbol{B}\mathop\emph{\text{div}}\nolimits \boldsymbol{A}$  
    $\displaystyle +(\boldsymbol{B}\cdot\mathop{\emph ▽}\nolimits )\boldsymbol{A}-(\boldsymbol{A}\cdot\mathop{\emph ▽}\nolimits )\boldsymbol{B}$ (738)
       
$\displaystyle \mathop\emph{\text{div}}\nolimits (\mathop\emph{\text{grad}}\nolimits f)$ $\displaystyle =$ $\displaystyle \mathop{\emph ▽}\nolimits ^2f$ (739)
$\displaystyle \mathop\emph{\text{rot}}\nolimits (\mathop\emph{\text{grad}}\nolimits f)$ $\displaystyle =$ $\displaystyle \boldsymbol{0}$ (740)
$\displaystyle \mathop\emph{\text{grad}}\nolimits (\mathop\emph{\text{div}}\nolimits \boldsymbol{A})$ $\displaystyle =$ $\displaystyle \mathop\emph{\text{rot}}\nolimits (\mathop\emph{\text{rot}}\nolimits \boldsymbol{A})+\mathop{\emph ▽}\nolimits ^2\boldsymbol{A}$ (741)
$\displaystyle \mathop\emph{\text{div}}\nolimits (\mathop\emph{\text{rot}}\nolimits \boldsymbol{A})$ $\displaystyle =$ 0 (742)
$\displaystyle \mathop\emph{\text{rot}}\nolimits (\mathop\emph{\text{rot}}\nolimits \boldsymbol{A})$ $\displaystyle =$ $\displaystyle \mathop\emph{\text{grad}}\nolimits (\mathop\emph{\text{div}}\nolimits \boldsymbol{A})-\mathop{\emph ▽}\nolimits ^2\boldsymbol{A}$ (743)


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: パラドックスの解答 : 電磁気学 : 電磁気学のラグランジアン   目次   索引
Yoichi OKABE 平成21年7月3日